LeetCode_Length of Last Word

Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters “ ”, return the length of last word in the string. If the last word does not exist, return 0.
（字符串最后一个单词的长度）

Note:
A word is defined as a character sequence consists of non-space characters only.

Example:

1. 字符串处理

本题考查python中基本的字符串处理函数，比较简单。具体实现方法如下：
（其中之所以需要使用 strip() 是因为当字符串为 “a ” 时，最后一个单词应该是 “a”）

class Solution:
    def lengthOfLastWord(self, s):
        """
        :type s: str
        :rtype: int
        """
        result = 0

        words = s.strip().split(' ')

        if len(words) == 0:
	        return 0
        else:
	        return len(words[-1])