LeetCode_Word Break

Word Break

Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine if s can be segmented into a space-separated sequence of one or more dictionary words.
(字符串是否可以有效分词)

Note:

  1. The same word in the dictionary may be reused multiple times in the segmentation.
  2. You may assume the dictionary does not contain duplicate words.

Example:



1. 动态规划

具体实现方法如下:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
class Solution:
def wordBreak(self, s: str, wordDict: List[str]) -> bool:
if s in wordDict:
return True

dp = [False for _ in range(len(s) +1)]
dp[0] = [True]

for i in range(1, len(s)+1):
for j in range(i):
if s[j:i] in wordDict and dp[j]:
dp[i] = True

return dp[-1]